Number System Sample Question Practice Exercise For Quiz and Assignment or home work
Digits of different number systems are given below:
Base 32 | Base 24 | Base 16 | Base 10 |
0 | 0 | 0 | 0 |
1 | 1 | 1 | 1 |
2 | 2 | 2 | 2 |
3 | 3 | 3 | 3 |
4 | 4 | 4 | 4 |
5 | 5 | 5 | 5 |
6 | 6 | 6 | 6 |
7 | 7 | 7 | 7 |
8 | 8 | 8 | 8 |
9 | 9 | 9 | 9 |
A | A | A | |
B | B | B | |
C | C | C | |
D | D | D | |
E | E | E | |
F | F | F | |
G | G | ||
H | H | ||
I | I | ||
J | J | ||
K | K | ||
L | L | ||
M | M | ||
N | N | ||
O | |||
P | |||
Q | |||
R | |||
S | |||
T | |||
U | |||
V |
Q1. 4.5 Marks
Solve this question without converting the numbers into Base 10
a. Convert (1110)2 to base-8
001 110
(16)8
b. Convert (10000101110)2 to base-16
0100 0010 1110
(42E)16
c. Convert (1111100000111010101)2 to base-32
01111 10000 0111010101
(FGEL)32
Q2. 4.5 Marks
a. Convert (123)9 to base-10
1x92 + 2x91 + 3x90 = 81 + 18 + 3 = (102)10
b. Convert (12)32 to base-16
1x321 + 2x320 = 32 + 2 = (34)10
34 ÷ 16: quotient = 2, remainder = 2
2 ÷ 16: quotient = 0, remainder = 2
Answer: (22)16
c. Convert (15)10 to binary
15 ÷ 2 =
quotient | Remainder | |
15 ÷ 2 | 7 | 1 |
7 ÷ 2 | 3 | 1 |
3 ÷ 2 | 1 | 1 |
Answer: (1111)2
